how to replace . with ..\

Raju Sathliya

Hi all,

Please look at below eg.

..abc\efg.

in this I want to replace only last . (dot) with ..\ (double dot slash)

So can anybody help on this...It will be greatly appreciated

Thanks,
Raju

numberwhun

What have you tried so far to do this? This is a learning forum and I would not want to take the opportunity to figure it out away from you. We can certainly help you, but please show us what code you have tried thus far.

Regards,

Jeff

nithinpes

You need to escape '.' and '\' using backslash(\) to remove thier special meaning inside pattern match.

how to replace . with ..\

re: how to replace . with ..\

re: how to replace . with ..\

Similar Perl bytes

/bytes/development

/bytes/it

/bytes/about