//b[1]//c gives different results if the first b is nested in anotherelement

<a>

<c/><c/>


<c/><c/><c/>


<c/>

</a>

Doing //b[1]//c on that yields two items. If, however, I put the
first </bwithin a <d></d>, I get five items. My question is...
why?

Here's what I mean by "put the first </bwithin a <d></d>":

<a>
<d>

<c/><c/>

</d>

<c/><c/><c/>


<c/>

</a>

Why does that return 5 items when the first only returns 2?

yawnmoth wrote:

Quote:

<a>

<c/><c/>


<c/><c/><c/>


<c/>

</a>
>
Doing //b[1]//c on that yields two items. If, however, I put the
first </bwithin a <d></d>, I get five items. My question is...
why?
>
Here's what I mean by "put the first </bwithin a <d></d>":
>
<a>
<d>

<c/><c/>

</d>

<c/><c/><c/>


<c/>

</a>
>
Why does that return 5 items when the first only returns 2?

//b[1] means select all b that are the first b child of their parent.
If you want to select the first b descendant use
/descendant::b[1]

David

--
http://dpcarlisle.blogspot.com

//b[1]//c gives different results if the first b is nested in anotherelement

re: //b[1]//c gives different results if the first b is nested in anotherelement

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