uncaught exception: permission denied to call XmlHttpRequest.open

sbettadpur · #1 September 2nd, 2008, 07:16 AM

hello

I am using xmlHttpRequest method in my application, this method is giving problem in the following browsers

1) Internet Explorer 7
2) Mozila Firefox(2.0.0.16)

I got solution for Mozilla issue

let me explain what i did

In the about:config (for this we have to open browser and type in the address bar as about:config, after that in filter place type as signed) of mozilla brower
you need to set 'signed.applets.codebase_principal_support' to true and add the line

'netscape.security.PrivilegeManager.enablePrivileg e("UniversalBrowserRead");

in my script(means above xmlHttpRequest.open)

But I am facing this issue in IE7 there i am getting Permission Denied to open xmlHttpRequest.

Anybody knows solution for this problem

gits · #2 September 2nd, 2008, 04:12 PM

i guess you want to start a 'cross-domain-request'? it is generally a very! bad idea to rely on settings to a browser-config ... unless it is an intranet application. you may probably find this helpful?

kind regards

sbettadpur · #3 September 5th, 2008, 05:56 AM

hello,

Thanks for ur reply, i saw the url what u provided in the message

and i added the following below lines in my code but its still not working

Expand|Select|Wrap|Line Numbers

 var xmlHttp = null;

if (window.XMLHttpRequest) {

  // If IE7, Mozilla, Safari, and so on: Use native object.

  xmlHttp = new XMLHttpRequest();

}

else

{

  if (window.ActiveXObject) {

     // ...otherwise, use the ActiveX control for IE5.x and IE6.

     xmlHttp = new ActiveXObject('MSXML2.XMLHTTP.3.0');

  }

}

Is it correct what i am doing please give me solution.

thanks

gits · #4 September 5th, 2008, 07:26 AM

was i correct with the assumption that you want to make cross-domain requests?

Ferris · #5 September 5th, 2008, 07:46 AM

I quite agree with gits. You probably want to make a cross-domain requests. Could you post more code for detail?

sbettadpur · #6 September 6th, 2008, 06:13 AM

here with i am sending my full source code

Expand|Select|Wrap|Line Numbers

 <?php
 
?>
 
<html>

<head>

<script type="text/javascript" src="config_js_var.js"></script>

<script type='text/javascript'>
 
var xmlHttp
 
function get_username()

{

    xmlHttp=GetXmlHttpObject()

    if (xmlHttp==null)

     {

        alert ("Browser does not support HTTP Request")

         return

     }

    var url=getldap_username_utility_url;

    xmlHttp.onreadystatechange=getusername;

    xmlHttp.open("GET",url,true)

    xmlHttp.send(null)

}

function getusername()

{

    var username;

    if (xmlHttp.readyState==4 || xmlHttp.readyState=="complete")

    {

         usernamestring=xmlHttp.responseText
 
        userarr = usernamestring.split("<!");
 
        domainusername = userarr[0];
 
        domainuserarr = domainusername.split("\\");
 
        username = domainuserarr[1];

        domain = domainuserarr[0];

        var params;
 
        params = "user="+username;
 
        window.location=feedbackforum_url+"?user="+username+"&domainname="+domain;

    }

}
 
function GetXmlHttpObject()

{

    var xmlHttp=null;

    try

     {

         // Firefox, Opera 8.0+, Safari

         xmlHttp=new XMLHttpRequest();

     }

    catch (e)

     {

         //Internet Explorer

         try

          {

              xmlHttp=new ActiveXObject("Msxml2.XMLHTTP");

          }

         catch (e)

          {

              xmlHttpn=new ActiveXObject("Microsoft.XMLHTTP");

          }

    }

    return xmlHttp;

}
 
</script>
 
</head>
 
<body onload='get_username();'>
 
</body>

</html>

Ferris · #7 September 6th, 2008, 12:06 PM

Hi, would you please tell me the value of "getldap_username_utility_url" ?

acoder · #8 September 6th, 2008, 12:21 PM

You can use a web proxy for cross-domain requests. Another alternative is a dynamic script tag.

acoder · #9 September 6th, 2008, 04:16 PM

I'll just point out that dynamic script tags are for JavaScript/JSON only, so may not be useful here. One other alternative is Apache's mod_rewrite, if that's possible.

uncaught exception: permission denied to call XmlHttpRequest.open

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