regular expression question

Hi,

I have a span that contains text of the form

var spanHtml = "My Tab Content (7)";

The content is guaranteed to end with a string of the form "(#)" where
"#" is a whole number. My question is, how would I write a regular
expression that would change the value of #, given another number?
For example, given the above variable, if I had

var newNumber = 15;

I would want the variable spanHtml to contain

"My Tab Content (15)".

Thanks, - Dave

re: regular expression question

laredotornado@zipmail.com wrote:var str1 = 'My Tab Content (7)';
var _regexp = /[0-9]+/;
alert(str1.replace(_regexp, '15'));

I make no claims that this is the best possible solution. My Regular
Expression knowledge is severely limited.

One small change could be, since you know it is always (#):

var _regexp = /\([0-9]+\)/;
alert(str1.replace(_regexp, '(15)');

Again though, I am sure a regexp guru will along momentarily to suggest
an improvement.

--
-Lost
Remove the extra words to reply by e-mail. Don't e-mail me. I am
kidding. No I am not.

re: regular expression question

laredotornado@zipmail.com wrote on 16 mei 2007 in comp.lang.javascript:
function doit(s,n) {
return s.replace(/\(\d+\)$/,'('+n+')')
}

alert(doit("My Tab Content (7)",15))
alert(doit("Blah Blah (12345)",128))


--
Evertjan.
The Netherlands.
(Please change the x'es to dots in my emailaddress)

re: regular expression question

On May 16, 2:22 pm, "laredotorn...@zipmail.com"
<laredotorn...@zipmail.comwrote:var content="My Tab Content (7)"
var regexp=/\d+(?=\)$)/
content=content.replace(regexp,8)

or

var content="My Tab Content (7)"
content=content.slice(0,-2)+8+content.slice(-1))

re: regular expression question

In comp.lang.javascript message <8P-dneqFHrL179bbnZ2dnUVZ_jadnZ2d@comcas
t.com>, Wed, 16 May 2007 17:07:51, -Lost <maventheextrawords@techie.com>
posted:Then why respond?
Then why respond so soon?

spanHtml = spanHtml.replace(/\d/, 15) ;

If the input may contain multiple digits, change \d to \d+ .
If the input may be signed, precede /d by [+-]? .

It's a good idea to read the newsgroup c.l.j and its FAQ. See below.

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re: regular expression question

Dr J R Stockton said the following on 5/17/2007 11:40 AM:So that people like you can respond and try to needle them? Believe it
or not, a lot of people here post in the hopes of learning. Whether it
is by answering questions or by posting questions.

--
Randy
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