helping with regex in java.

ndedhia1

If I have a line that contains this: ProdBC02TradeServer24
and I want to break it up into BC02 and 24, how would I go about doing that.

Right now,
I am doing this: Prod(BC\\d+)\\S+(\\d+)
But that only breaks it up into:
BC02 and 4. I need 24, not just the 4.
Can someone show me what I am doing wrong

Thanks
Nirav

jkmyoung

The problem is that the regex picks the shortest match, eg the match with only 1 digit. I suggest adding the next character, whether that be space, end of line, eof, or other.

What class are you using to execute the regexp?

ndedhia1

I am importing these two lines:

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import java.util.regex.Matcher;

import java.util.regex.Pattern;

I am defining the regex expressing in a variable here:

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public static String TSAssingmentFilter = "Prod(BC\\d+)\\S+(\\d+)\\s+(\\w+)\\s+\\S+\\s+(\\d+)\\s+(\\S*)\\s+(\\d+)";

I am using this function to use the regex expression on the specific line:

Expand|Select|Wrap|Line Numbers

if(OutlierUtilities.getInstance().match(line,TSAssingmentFilter))

I am using this function to grep out what i am looking for:

Expand|Select|Wrap|Line Numbers

 
public boolean match(String line,String regExp)

     {

              pattern = Pattern.compile(regExp);

              matcher = pattern.matcher(line);

              return matcher.find();

     }

jkmyoung

Insert a non digit character afterwards: \D or [^\d], and change the \\s+ to a \\s?

ndedhia1

so instead of this: Prod(BC\\d+)\\S+(\\d+)

are you saying I should try this: Prod(BC\\d+)\\S\\D(\\d+)

jkmyoung

"Prod(BC\\d+)\\S+(\\d+)\\s+ ..."to
"Prod(BC\\d+)\\S+(\\d+)[^\\d]\\s?..."

ndedhia1

Im sorry...im having trouble in this part:
Prod(BC\\d+)\\S+(\\d+)
But that only breaks it up into:
BC02 and 4. I need 24, not just the 4.

So i changed it to this and it worked:

Expand|Select|Wrap|Line Numbers

 
public static String TSAssingmentFilter = "Prod(BC\\d+)\\S+\\D(\\d+)\\s+(\\w+)\\s+\\S+\\s+(\\d+)\\s+(\\S*)\\s+(\\d+)";

THANKS A LOT FOR YOUR HELP!!!

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