Quote:
Originally Posted by vinothg
Hi ,
I am migrating slowly from c++ to java. The output of the following program differs from c++ in java. It should be really easy for any java programmer to explain. Just an hint could help me to understand.
class base {
public void f(){
System.out.println("base.f()");
g();
}
public void g(){
System.out.println("base.g()");
}
}
class derived extends base {
public void g(){
System.out.println("derived.g()");
}
}
public class bade{
public static void main(String[] args){
base p = new derived();
p.f();
}
o/p in java -> base.f(), derived.g()
o/p in c++ -> base.f(),base.g().
Yes buddy .............. at the beginning you are trying to understand the base concept of Java.
Really happy to see that :-)
Actually Java resolves these during runtime.
Have a look at "Class","Method" and it's relevant classes.
Then you will understand that by yourself.
Debasis Jana
