Quote:
Originally Posted by hoho2san
Hi..can anybody give coding for:
user input number of random number to generate.
then, add it to array.
the output like this:
array A = [ 1 2 2 3 4 5 6 2 2]
array B = [ 1 2 3 4 5 6 ]
*the repeat number in array A will not be display again in array B
now im still doing coding for it..
Here is a solution with an amazing number of for loops:
- import java.io.*;
-
public class Duplicates {
-
public static void main(String[] args) {
-
BufferedReader inFile = null;
-
-
try {
-
inFile = new BufferedReader(new InputStreamReader(System.in));
-
System.out.print("Enter number of numbers to be entered: ");
-
int a = Integer.parseInt(inFile.readLine());
-
System.out.println("Enter the numbers one by one");
-
int[] array = new int[a];
-
for(int i = 0; i < array.length; i++) {
-
array[i] = Integer.parseInt(inFile.readLine());
-
}
-
int[] temp = new int[a];
-
int j = 0; int count = 0;
-
for(int i = 0; i < array.length; i++) {
-
if(!Duplicates.in(temp, array[i])) {
-
temp[j++] = array[i];
-
count++;
-
}
-
}
-
int[] noDup = new int[count];
-
for(int i = 0; i < count; i++) {
-
noDup[i] = temp[i];
-
}
-
-
-
System.out.print("\nOriginally entered: ");
-
for(int i = 0; i < array.length; i++) {
-
System.out.print(array[i] + " ");
-
}
-
System.out.print("\nWith duplicates removed: ");
-
for(int i = 0; i < noDup.length; i++) {
-
System.out.print(noDup[i] + " ");
-
}
-
-
}
-
catch(Exception e) {
-
e.printStackTrace();
-
}
-
}
-
public static boolean in(int[] a, int x) {
-
boolean isIn = false;
-
for(int i = 0; i < a.length; i++) {
-
if(a[i] == x) {
-
return true;
-
}
-
}
-
return isIn;
-
}
-
-
}
