Why there is no distinction between signed and unsigned float types?

SchoolOfLife

Hello,

When I try compiling this code:

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signed float fl1=-10e-2;

with variable declarations of type signed float and unsigned float, gcc 3.3.5 outputs:

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error: short, signed or unsigned invalid for `fl1'

"Why there is no distinction between signed and unsigned float type in C++?"

Thanks...

SchoolOfLife

I searched google and found some satisfactory answers. (e.g. link. So, imo my problem is solved now. I should have tried searching before I posted this thread. Nevermind

Thanks anyways,

Why there is no distinction between signed and unsigned float types?

re: Why there is no distinction between signed and unsigned float types?

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