number of elemnts in an array

Arepi

Hi,

I have function which return whit en double* array.
I tried this to get the size :

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 double  array[100];
 
double* Function()

    {

           // some code

           return array;

        }
 
int main(int argc, char *argv[])

    {

           double *getarray = Function();

           int  size = sizeof(getarray) / sizeof(getarray[0]);

        }

If I print out the "getarray" variable it give some data, but the value of "size" is 0.
Can anyone explain what's wrong?

Thanks

Arepi

YarrOfDoom

You're dividing the size of a pointer (so probably 1 byte as result) by the size of an element of the array (which is a double, and therefore more than one byte). The result of this would be less than zero, but since it's saved in a variable of the type int, that number is rounded down to zero.
As far as I know, the most common solution to this problem is to pass the length of the array along with the array itself.

number of elemnts in an array

re: number of elemnts in an array

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