Finding all open windows

MrPickle

I am trying to get all open windows on windows. I have looked around and seen that I should use EnumWindows and EnumWindowsProc so I whipped up this code to test it but it tells me there's 300-400 windows open, and I only have about 5?

Expand|Select|Wrap|Line Numbers

 #include <windows.h>

#include <iostream>
 
int i;
 
BOOL CALLBACK EnumWindowsProc(HWND hWnd, LPARAM lParam);
 
int main(int argc, char** argv) {

    std::cout << "Finding all open windows\n";

    if(EnumWindows(EnumWindowsProc, 0)) {

        std::cout << i << " windows are open\nCall was successful...\n" << std::endl;

        std::cin.get();

    } else {

        std::cout << "Call was unsuccessful...\n" << std::endl;

        std::cin.get();

    }
 
    return 0;

}
 
BOOL CALLBACK EnumWindowsProc(HWND hWnd, LPARAM lParam) {

    i++;

    return true;

}

donbock

Caveat: I'm not a Windows programmer; and I've never used EnumWindows.

1. I suggest setting variable "i" to zero just before calling EnumWindows. It won't fix your problem, but it is a good habit to get into.

2. Could EnumWindows be revisiting the same windows? The way to check that is to accumulate a list of the window handles passed to EnumWindowProc (hWnd) and check if there are any duplicates.

MrPickle

After adding the check, I think it may be getting hidden programs too because outputting the program's text gives allot of blanks and things like my laptop's battery life.

Thanks :)

Finding all open windows

re: Finding all open windows

re: Finding all open windows

Similar C / C++ bytes

/bytes/development

/bytes/it

/bytes/about