this poster tends to post with low information content
but high abuse content.
On Nov 2, 6:30*am, Nomen Nescio <nob...@dizum.comwrote:
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lancer6...@yahoo.com said:
<snip>
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[i] saw a function header defined as:
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int Function(int value1, int value2, (int *A)(void *A1, int *A2, void
*A3), void *A3)
This specifies that parameter A is a pointer to a function
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and the function is called by
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Function(value1, value2, A, A3);
'A' would be the name of a function. C automatically converts the name
into
a pointer to a function. The term used in the standard is "decays to
a
function pointer"
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Is the "(int *A)(void *A1, int *A2, void *A3)" in the function header
equivalent to passing a function (A) to another function (Function)?
it specifies that the parameter is a function pointer
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Practically speaking, yes. In CLC-talk, no. Numerous semanticists,
postmodernists,
<snip>
your word salad seems more PoM than anything else I've
seen recently on clc.
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Something to think about
: If "(int *A)(void *A1, int *A2, void *A3)"
were replaced by "int A[]", would an entire array be passed to
Function() or something else?
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If so, how are the arguments to A passed into Function when Function
is called?
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They're not, at least not in the sense you probably think.
ok. It is specified that the parameter is a pointer to a function.
The parameters aren't passed here. You needd to look at the call
to A that, presumably, appears in Function().
<snip nonsense>
--
Nick Keighley
