On Wed, 27 Aug 2008 00:07:35 -0700, MN wrote:
[snip]
Quote:
>
for (i = 0; i < in2; i++)
{
if (i == 0)
{
Quote:
//printf("- %d\n", &view_var1[i]);
printf("- %d\n",var1[i]);
}
{
Quote:
//printf("%d %d\n", i-1, &view_var1[i]);
> printf("%d %d\n", i-1, var1[i]);
}
Quote:
}
return 0;
>
}
>
int* function(int in1, int in2)
{
int i = 0;
if (var1 != NULL)
free(var1);
var1 = (int*)malloc (sizeof(int*)* in2);
>
>
for (i = 0; i < in2; i++)
{
if (i == 0)
var1 [i] = 0;
else
{
if (i == 1)
var1[i]= 1;
else
var1[i] = var1[i-1]*2+in1;
}
}
return (var1[in2]);
}
>
The return type is int* but here you return int. The correct
way would be to write:
return var1+in2;
But then again, that just returns a pointer pointing beyond the
allocated array. I'm guessing you actually want the beginning
of the array:
return var1;
--
OU
