Local array scope

Hi,

When the method "foo" ends, shouldn't the arr[2] array be gone (due to
scope termination) and the pointer in class A be invalid? However,
when I run the program, I get "2". It seems to that I get this result
by luck; in further executions, I may get some other value. Am i
right?
class A
{
public:
A( int* ptr ){ arr = ptr; }
int* getArr(){ return arr; }
private:
int* arr;
};

A foo( )
{
int arr[2] = {2,1};
return A( arr );
}

int main()
{
A a = foo();
int* arr = a.getArr();

cout << arr[0] << endl; // This is not ambigous, since arr has
actually gone out of scope, am i right?
return 0;
}

re: Local array scope

D. Susman wrote:
Yes.
You dereference an invalid pointer. Anything can happen, including a value
of 2.
Yes.
"Ambiguous" ????

It is undefined behavior. That's all.

Best

Kai-Uwe Bux