printf of the "%d" string

jorba101 · #1 June 16th, 2008, 10:07 AM

How to printf the string "%d" itself?

I wonder how should I escape the %, since I see no escape char for % (in http://www.acm.uiuc.edu/webmonkeys/book/c_guide/1.1.html)

Thanks!

Banfa · #2 June 16th, 2008, 10:36 AM

There is not escape code for % because it doesn't need one. However there is a format code for % because in the context of a printf it does need one.

Read this: http://www.acm.uiuc.edu/webmonkeys/b...2.html#printf]

gpraghuram · #3 June 17th, 2008, 02:03 AM

To print % you should use % as the escape sequence.
Code will be

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printf("%%");

will print %

Raghu

shivapadma · #4 June 26th, 2008, 05:57 PM

char a[3]="%d";
printf("%s",a);

by using above two lines u can print %d itself

gpraghuram · #5 June 27th, 2008, 02:35 AM

Quote:

Originally Posted by shivapadma

char a[3]="%d";
printf("%s",a);

by using above two lines u can print %d itself

I think the %% option would be much easier as u need not declare the local variable.

Raghuram

jorba101 · #6 June 27th, 2008, 08:23 AM

Yep,

In the end I did something like

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printf("%%d");

It was meant to construct the string to pass later on to an fscanf() while reading a file.

Thanks,

gpraghuram · #7 June 30th, 2008, 02:11 AM

Quote:

Originally Posted by jorba101

Yep,

In the end I did something like

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printf("%%d");

It was meant to construct the string to pass later on to an fscanf() while reading a file.

Thanks,

Hi,
You want to print % to console or have the % in a string to pass it to another function?

Raghu

jorba101 · #8 June 30th, 2008, 07:16 AM

I pass it to another function. Actually I was using sprintf() for that.

gpraghuram · #9 July 3rd, 2008, 02:33 AM

Quote:

Originally Posted by jorba101

I pass it to another function. Actually I was using sprintf() for that.

If u are using sprintf then u can follow the same idea

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char arr[100];

sprinf(arr,"%%");

Then u can pass arr to the function u are using.

Raghu

printf of the "%d" string

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re: printf of the "%d" string

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