On Mar 18, 11:14*am, "jason.cipri...@gmail.com"
<jason.cipri...@gmail.comwrote:
Quote:
Note that if there is an x or a y (or in your case a y_) in a larger
scope, then it will use the larger scoped one instead:
>
int x = 0, y = 0;
>
void function () {
* int x(x); // now it uses x from above
* int y = y; // same here
>
}
No, both x and y are still being initialized with their own
indeterminate values - the x and y declarations in the outer scope
make no difference here. In short, the inner x and y declarations hide
the outer ones.
There is one notable exception, however:
const int i = 2;
{
int i[i];
}
In this case, the inner "i" declares an array of two ints.
Greg
