forcing char array to act as int array

Hello,
I am trying to 'force' a character array to act as an int array. I
want to use 4 chars to store an actual int , in the array, not a number
converted to a string. So every 4 characters of my array is really a
full integer value.

Can anyone post a simple example on how to do this?

Thanks,
chuck

re: forcing char array to act as int array

On 14 Ún, 13:45, chuck <noem...@gmail.comwrote:You need int type, where sizeof() is 4. Then:

char* buffer = "abcdefghijklmnopqrstuvwx";
int32_t* ibuffer = reinterpret_cast<int32_t*>(buffer);

re: forcing char array to act as int array

On Feb 14, 7:45*am, chuck <noem...@gmail.comwrote:
Are the ints in your system sizeof( 4 )? Is the memory in the char
array formatted with the same endian as what the system uses?

If so, then simply int* myArr = reinterpret_cast<int*>( myChar );
Otherwise, you will have to do some real work converting the raw
memory into the format you need.

re: forcing char array to act as int array

Daniel T. wrote:

They'd have to be, wouldn't they?




Brian

re: forcing char array to act as int array

On 14 Feb., 13:45, chuck <noem...@gmail.comwrote:Do it the other way around: regard your integer variable as an array
of four (if that is the size of your int) characters and std::copy to/
from the ints.

/Peter

re: forcing char array to act as int array

On Feb 14, 7:48 pm, "Daniel T." <danie...@earthlink.netwrote:That's a good recepe for a core dump on a lot of machines.
You're forgetting alignment considerations.
No real work, just a bit of shifting and masking.

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