getting the size of dynamic array

abdulsamad

Hello there
i wanna get the the size of a dynamic array of integer type which i have created like that.........

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            int *arr=0;

           arr = createTempArray();

           arr =  storeRowValues(arr);

           arr =  storeColValues(arr);

           check(arr);

         }

        }

     }

    int* createTempArray()

      {

        int length = rowIndex+colIndex;

        int *tempArray = new int[length];

         return tempArray;

      }

      int *storeRowValues(int *tempArr)

      {

        for(int i=0;i < colIndex; ++i)

        {

           tempArr[i]=array[rowIndex][i];

        }

        return tempArr;

      }

      int *storeColValues(int *tempArr)

      {

      int size = sizeof(tempArr) / sizeof(tempArr[0]);
 
        for(int i=0; i < size; i++)

         { if(tempArr[i]==7)

           {

        --i;

        break;

           }

         }

I wanna get the the value of size in

storeColValues(int *tempArr) method ..............

**********code***********

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int size = sizeof(tempArr) / sizeof(tempArr[0]);

this line always gives me a result of 1

somebody please help me and give me some hint or piece of code so that i can find the size correctly........

Ganon11

When you pass an array (or pointer to an array) to a function, the function doesn't know for certain if it is an array or not - it just gets an address. It assumes this address is pointing to 1 - and only 1 - element. Thus, the sizeof(array) call returns the size of that pointer, not the size of the entire array.

The only way for a function to know the size of an array is to pass the length as an argument, or use the length as a global constant variable.

Studlyami

In visual c++ you can use the _msize() to get the size of the dynamic array. This is not a standard c++ function so it is not portable. Other than that you are stuck with having to create a variable for the array size.

getting the size of dynamic array

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