3 level inheritance heirarchy

I have trying to set up a three level inheritance heirarchy (see files
test.h/cpp below). When I compile this code using g++, I get the
following errors:
>
bash-3.00$ g++ test.cpp
test.cpp: In constructor `Lev2::Lev2(int, int, int)':
test.cpp:33: error: no matching function for call to `Lev0::Lev0(const
void**)'
test.h:27: note: candidates are: Lev0::Lev0(const Lev0&)
test.cpp:6: note: * * * * * * * * Lev0::Lev0(int)
>
Can someone please explain whats going on and how I can fix this
problem. Please see code below. If I remove the classes ILev2 and Lev2
everything compiles fine. Thanks
>
//-------------------------- FILE: test.h --------------------------//
>
#include <iostream>
#include <iomanip>
>
class ILev0
{
*public:
* virtual ~ILev0() {}
* virtual void PrintLev0() = 0;
>
};
>
class ILev1: public virtual ILev0
{
*public:
* virtual ~ILev1() {}
* virtual void PrintLev1() = 0;
>
};
>
class ILev2: public virtual ILev1
{
*public:
* virtual ~ILev2() {}
* virtual void PrintLev2() = 0;
>
};
>
class Lev0: public virtual ILev0
{
*public:
* Lev0(int nNum);
* virtual void PrintLev0();
>
*protected:
* int m_nNum0;
>
};
>
class Lev1: public virtual Lev0, public virtual ILev1
{
*public:
* Lev1(int nNum0, int nNum1);
* virtual void PrintLev1();
*protected:
* int m_nNum1;
>
};
>
class Lev2: public virtual Lev1, public virtual ILev2
{
*public:
* Lev2(int nNum0, int nNum1, int nNum2);
* virtual void PrintLev2();
*protected:
* int m_nNum2;
>
};
>
//-------------------------- FILE: test.cpp ------------------------//
#include "test.h"
>
//-------
>
Lev0::Lev0(int nNum)
* :m_nNum0(nNum)
{
>
}
>
void Lev0::PrintLev0()
{
* std::cout << "Lev0 Num: " << m_nNum0 << std::endl;
>
}
>
//-------
>
Lev1::Lev1(int nNum0, int nNum1)
* :Lev0(nNum0),
* *m_nNum1(nNum1)
{
>
}
>
void Lev1::PrintLev1()
{
* std::cout << "Lev1 Num: " << m_nNum0 << ", " << m_nNum1 <<
std::endl;
>
}
>
//-------
>
Lev2::Lev2(int nNum0, int nNum1, int nNum2)
* :Lev1(nNum0, nNum1),
* *m_nNum2(nNum2)
{
>
}
>
void Lev2::PrintLev2()
{
* std::cout << "Lev2 Num: " << m_nNum0 << ", " << m_nNum1 << ", " <<
m_nNum2 << std::endl;
>
}
>
//---
>
main()
{
* Lev0 *b = new Lev0(10);
* b->PrintLev0();
>
}
>
//------------------------------------------------------------------//
>
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On Dec 21, 2:05 pm, inte...@interec.net wrote:
>
>
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
Call to Constructor of Lev0 class is missing in the Lev2 constructor.
Resolution is to either implement default constructor in Lev0 class or
make a call to Lev0 constructor in the constructor of Lev2 as follows:
Lev2::Lev2(int nNum0, int nNum1, int nNum2)
:Lev1(nNum0, nNum1),Lev0(nNum0),
m_nNum2(nNum2)
{
>
}

On Dec 21, 2:34 am, Sachin <sachinc.bira...@gmail.comwrote://------------------------------------------------------------------//>
Lev2 constructor explicitly calls Lev1 constructor and Lev1 constructor
explicitly calls Lev0 constructor so why do I need to add a call to Lev0
constructor in Lev2 ?

On Fri, 21 Dec 2007 08:44:17 -0800, interec wrote:>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
Because it's a virtual base class.
>
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>
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