copy ctor

I thought the copy ctor always takes the form
Test::Test(const Test & arg);
for a class Test.

But I read the following sentence in Stanley Lippman's C++ Primer 4th
Edition(Page 476):

The copy constructor is a special constructor that has a single
parameter that is a (usually const) reference to the class type.

My doubt
--------------
Since the above sentence contains "(usually const)" in parantheses,
does it mean that we may need a copy ctor that takes the form
Test::Test(Test & arg) ?
(that is, reference to plain type) ?

Kindly let me know when we will need this second form.

Thanks
V.Subramanian

re: copy ctor

On 2007-09-25 16:44, subramanian100in@yahoo.com, India wrote:Yes, you might have a need for a non-const copy constructor, but I can
frankly not come up with a situation where you would. Perhaps if you
want to have special copy construction for some argument types (const
and temporaries), then you could declare both a const and a non-const
copy constructor.

Please also not that the copy constructor does not have to take only one
argument, as long as there are default values for the other arguments.

--
Erik Wikström

re: copy ctor

Erik Wikström wrote:
std::auto_ptr<is an example. It has a non-const copy constructure since
copying involves transfer of ownership and changes the source object.

[snip]


Best

Kai-Uwe Bux

re: copy ctor

On Sep 25, 9:15 pm, Kai-Uwe Bux <jkherci...@gmx.netwrote:

[...]And look at all the hoops std::auto_ptr has to jump through so
you can e.g. return it from a function.

--
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