problem with if statement

stmfc

whats wrong with this function:

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 int max(int x, int y) {

    return (if (x > y) { return x; } else { return y; });

}

i get an "expected an expression" error

zodilla58

Use this instead:

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 int max(int x, int y)

{

    if (x > y)

        return x; 

    else

        return y;

}

Regards

stmfc

Quote:

Originally Posted by zodilla58

Use this instead:

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 int max(int x, int y)

{

    if (x > y)

        return x; 

    else

        return y;

}

Regards

thanks for the reply.
i know that there are many alternative ways to perfom that functionality.
what i want to figure out is the rule which doesnt allow the above code to be considered as legal

zodilla58

Quote:

Originally Posted by stmfc

thanks for the reply.
i know that there are many alternative ways to perfom that functionality.
what i want to figure out is the rule which doesnt allow the above code to be considered as legal

Your function has return type int. In your previous code, you have taken return withing return like:

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return(if(...) return x; else return y;)

That is not proper way to return the value.

dmjpro

Quote:

Originally Posted by stmfc

whats wrong with this function:

Expand|Select|Wrap|Line Numbers

 int max(int x, int y) {

    return (if (x > y) { return x; } else { return y; });

}

i get an "expected an expression" error

Try it.

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return x>y?x:y;

Kind regards,
Dmjpro.

weaknessforcats

Quote:

Originally Posted by stmfc

whats wrong with this function:

Code: ( text )
int max(int x, int y) {
return (if (x > y) { return x; } else { return y; });
}

i get an "expected an expression" error

The function has an int return type so you have to return an int. That means the code between the parentheses must evaluate to an int. It doesn't.

The key is in the "expected an expression" reported by the compiler. An expression must evaluate to true or false where false is 0 and true is not false.

if statements don't have a value.

problem with if statement

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