Parsing the content of string array into an integer

Originally Posted by Alien

error: parse error at end of input

Any help or suggestion is appreciated.

Originally Posted by JosAH

That is a compilation error; most likely you're missing a right curly brace near
the end of your code. Check them carefully and you'll find the missing one.

The atoi() function takes a '\0' terminated string and returns the int represented
by that string; it shouldn't be a problem if your array contains just digits.

kind regards,

Jos

Originally Posted by Alien

Yes, it my code was missing closing curly braces of main() function.

The problem I had was parseing error which after fixing the code is:

string.c: In function `main':
string.c:22: error: parse error before '{' token
string.c: At top level:
string.c:26: error: parse error before '}' token

Originally Posted by JosAH

Told you so ;-) We'd have to see the whole code if you want those parse errors
solved. Seeing the error diagnostic messages it has to do with curly brackets
that aren't balanced; same as the previous errors.

kind regards,

Jos

Originally Posted by Alien

Thanks. :) The code is just above.

Thanks for going through the trouble.

Originally Posted by JosAH

Huh? you edited your original post: see your text and the part I thought I quoted.
Now you're talking about a runtime error: you're invoking the atoi() function on a
single char; that is not correct; atoi() takes a pointer to char(s) as its parameter,
terminated by a '\0' char.

kind regards,

Jos

Originally Posted by mohammadazim

In your loop you can do following changes

for (i = 0; i < strlen(isbn); i++)
{
if(isdigit(isbn[i]))
{
char s[2];
s[1] = '\0';
s[0] = isbn[i];
numericisbn[i] = atoi(s);
printf("%d", numericisbn[i]);
puts("isdigit is working\n");
}
}

Since we have only one api(atoi) which converts integer strings to inytegers, it is better to make it a temp string and get an int.