printf() width specifier in text fields

Folks,

Can the width specifier be used in a printf() text string?

If I execute...

printf("%4s", ".........."); it prints ten dots.

If I execute

printf("%4s", "."); it prints one dot.

I was hoping to use sprintf to fill in a number of spaces in a field, such
as...

int spaces = 6;

sprintf(buf, "head %*s tail", spaces, " ");

If printf() can't do it, I know I can write a function that will handle it,
but is there a more elegant way? printf() would be attractive because I
would be able to fill in "head", "tail" and a given number of spaces between
them, all in one statement.

Thanks,

MikeC

--
Mental decryption required to bamboozle spam robots:

mike_best$ntlworld*com
$ = @
* = dot

re: printf() width specifier in text fields

MikeC wrote, On 22/07/07 11:29:printf("%4.4s","..........");
Are you sure it does not print 3 spaces and 1 dot? Try
printf('"%4s'", ".");
so you can see
I'm not entirely sure what you want. Possibly %*.*s specifying minimum
and maximum length.
You can probably do what you want. The number before the decimal point
is minimum width, after is maximum width, so both the same specifies
exact width. You can also use negative numbers to specify left justified
if that is what you want.
sprintf(buf, "%*.*s %*.*", -7,7,"head",-7,7,"tail");
Or whatever.
--
Flash Gordon

re: printf() width specifier in text fields

Thanks a million, Flash,

I learned something I didn't know from your post (that you can specify max
and min widths), but I independently found the answer to what I was looking
for by Googling around the web.

What I was missing was the + or - specifiers in the field. If I execute....

printf("%4s", "."); it prints a dot (no spaces). If I execute
printf("%-4s", "."); it prints three spaces and one dot (field width of 4).
If I execute
printf("%+4s", "."); it puts the dot at the other end of the field of 4 (a
dot, then three spaces)
If I replace the dot with a space, and execute
printf("%-4s", " "); it gives me three spaces followed by a space, which
is exactly what I wanted.

Thanks for your reply all the same - as I said, I learned something!

MikeC

"Flash Gordon" <spam@flash-gordon.me.ukwrote in message
news:ejpbn4x457.ln2@news.flash-gordon.me.uk...

re: printf() width specifier in text fields

MikeC wrote:
Try it this way and see what happens:

/* BEGIN new.c */

#include <stdio.h>

int main(void)
{
printf("%4s", ".");
printf("%4s", ".");
printf("%4s", ".");
printf("%4s", ".");
printf("%4s", ".");
putchar('\n');
return 0;
}

/* END new.c */

--
pete

re: printf() width specifier in text fields

Thanks Pete,

.... but I think you missed the point.

Regards,

MikeC

"pete" <pfiland@mindspring.comwrote in message
news:46A35151.5E61@mindspring.com...

re: printf() width specifier in text fields

MikeC wrote:Pete's point was to correct a misunderstnading you have about printf
specifiers. Understnnding that, you can get what you want with

printf ("foo%*sbar", nspaces, "");

to insert nspaces space characters between "foo" and "bar".

--
Thad

re: printf() width specifier in text fields

MikeC wrote:I disagree.
What you wrote is wrong:
No. It prints 3 spaces followed by a dot.
No. It prints a dot followed by 3 spaces.
No. It does the exact same thing as printf("%4s", ".");
It gives you a space followed by three spaces,
which is what you want,
but if you knew what you were talking about,
eventually you would have gotten to this expression:

printf("%4s", " ")

Try it again:

/* BEGIN new.c output */
.X
.. X
.X
X
X
/* END new.c output */


/* BEGIN new.c */

#include <stdio.h>

int main(void)
{
puts("/* BEGIN new.c output */");
printf("%4s", ".");
puts("X");
printf("%-4s", ".");
puts("X");
printf("%+4s", ".");
puts("X");
printf("%-4s", " ");
puts("X");
printf("%4s", " ");
puts("X");
puts("/* END new.c output */");
return 0;
}

/* END new.c */

--
pete