how is float arranged in memory

Ajayshankar

How is a float variable arranged in memory.. I know its 4 bytes.

but if I store 5.6 how is the bits arrangement of real and int part. how is the decimal point indicated.

dtimes6

Try this to find out:

#include <stdio.h>

int main()
{

float i=5.6;
unsigned char* a;
a = (unsigned char*)&i;
printf("%d, %d, %d, %d",*a, *(a+1), *(a+2), *(a+3));
return 0;
}

D_C

If I remember correctly, the first bit is the sign bit (+ or -). The next 23 bits are the mantissa, and the last 8 are the exponent.

They assume that the first bit will eventually be 1, so they don't store the most significant 1 bit. So (sign)*(1+the fractional mantissa)^exponent is the number stored.

how is float arranged in memory

re: how is float arranged in memory

re: how is float arranged in memory

Similar C / C++ bytes

/bytes/development

/bytes/it

/bytes/about