On 27 Sep 2006 14:33:42 -0700, "NightCrawler" <muley.rahul@gmail.com>
wrote:
Quote:
>Hi everybody i need code for converting integer no to roman i.i
>1->I,5->V n so on....
#include <stdio.h>
const char *roman_digits[] =
{"", "I", "II", "III", "IV", "V", "VI", "VII", "VIII", "IX"};
const char *roman_tens[] =
{"", "X", "XX", "XXX", "XL", "L", "LX", "LXX", "LXXX", "XC"};
const char *roman_hundreds[] =
{"", "C", "CC", "CCC", "CD", "D", "DX", "DXX", "DXX", "CM"};
const char *roman_thousands[] =
{"", "M"};
/* not really necessary */
void empty_keyb_buffer(void) { while (getchar()!='\n') ; }
int main()
{
int n, num_is_ok=0, digits, tens, hundreds, thousands;
while (!num_is_ok) {
printf("insert a number between 0 and 1999: ");
scanf("%d", &n);
empty_keyb_buffer();
num_is_ok=(n>=0)&&(n<=1999);
}
thousands=n/1000;
hundreds=(n%1000)/100;
tens=(n%100)/10;
digits=n%10;
printf("Roman equivalent: %s%s%s%s\n",
roman_thousands[thousands],
roman_hundreds[hundreds],
roman_tens[tens],
roman_digits[digits]);
return 0;
}
