tsar.omen@gmail.com wrote:[color=blue]
> Hello everyone,
> during my coding practice I have encounted the following problem:
>
> Vital code pieces:
>
>
> ---
> template <class T> class SmartPtr
>
> {
>
> private:
>
> Reference<T>* ref; // object with pointer to T and ref counter
>
> public:
>
> SmartPtr() : ref(0) {}
>
> SmartPtr(T* t) : ref(new Reference<T>(t)) {}
>
> SmartPtr(SmartPtr& h) : ref(h.acquire()) {}
>
> SmartPtr& operator = (T* t) {/**/}
>
> SmartPtr& operator = (SmartPtr& h) {/**/}
>
> ~SmartPtr() { freeReference(); }
>
> private:
>
> void freeReference() {/**/}
>
> Reference<T>* acquire () {/**/}
>
> };
> ---
>
>
> Now to introduce the problem:
>
> (1) works:
> SmartPtr<Foo> pFoo(new Foo()); // direct initialization
> (SmartPtr::SmartPtr(T*))
>
> (2) works:
> SmartPtr<Foo> pFoo1(new Foo());
> SmartPtr<Foo> pFoo2(pFoo1); // direct initialization
> (SmartPtr::SmartPtr(SmartPtr&))
>
> (3) works:
> SmartPtr<Foo> pFoo; // SmartPtr::SmartPtr()
> pFoo = new Foo(); // operator=(T *)
> pFoo = pFoo7; // operator=(SmartPtr&)
>
> !(4) does _NOT_ work:
>
> SmartPtr<Foo> pFoo = new Foo();
>
> It produces the following error on gcc 3.3.6:
>
> ---
> main.cc:24: error: no matching function for call to
> `SmartPtr<Point>::SmartPtr( SmartPtr<Point>)'
> smartptr.h:162: error: candidates are:
> SmartPtr<T>::SmartPtr(SmartPtr_ref<T>)
> [with T = Point]
> smartptr.h:73: error:
> SmartPtr<T>::SmartPtr(SmartPtr<T>&) [with T = Point]
> smartptr.h:70: error: SmartPtr<T>::SmartPtr(T*) [with T
> =
> Point]
> main.cc:24: error: initializing temporary from result of `
> SmartPtr<T>::SmartPtr(T*) [with T = Point]'
> ---
>
> AFAIK in case 'SmartPtr<Foo> pFoo = new Foo();' a copy initialization
> is used. That's firstly applying conversion operator to the right side
> and then calling a copy constructor. Because right side in in fast T* t
> so SmartPtr::SmartPtr(T*) was chosen, resulting in creation of
> temporary object and trying to copy initialize pFoo with tmp object
> which fails [SmartPtr<Point>::SmartPtr(SmartPtr<Point>) as reported by
> g++].
>
> My question is if it's possible to somehow fix it to allow construction
> like 'SmartPtr<Foo> pFoo = new Foo();' legal.
>
> Many thanks in advance.
>
> --
> zakkath[/color]
This is an issue of constness and an optimization. Specifically, some
initialization optimization is taking place in your fourth example but
because your parameter to the copy constructor is not const, you cannot
bind an rvalue to it. In short, you need to add const as such:
SmartPtr( const SmartPtr& h) : ref(h.acquire()) {}
Reference<T>* acquire() const {/**/}
Cheers! --M
