dbuser wrote:[color=blue]
> Hi,
> I have to implement every even and odd character swapping of a stream.
> My problem is with the following code is that if the stream has total
> even no of characters in it(including spaces) then it works, but when
> it has odd no of characters, then last characters is not written ,
> because it does not have i+1 element to swap. Here is what I am doing:
> Please suggest the correct way of doing this for any number of
> character.
> void swap( char * w) //array is read from a file and passed here.
> {
> int i,len = strlen(w);
> for ( i=0; i<len; i=i+2) {
> swapchar( &w[i], &w[i+1]);
> }[/color]
The problem is that on the last iteration you're swapping the last
normal character with the terminating '\0', in effect chopping one off
the end of the string. If you'd used std::string this wouldn't have
happened. :-)
#include <iostream>
#include <string>
#include <algorithm>
using namespace std;
void swap_adjacent(string& s){
for (int i = 0; i < s.size(); i+=2){
swap(s[i], s[i+1]);
}
}
int main(){
string s;
cin >> s;
swap_adjacent(s);
cout << s << endl;
}
