Finding template argument of child

I have the following situation:

class A
{
public:
virtual ~A() {}
};

template < typename T >
class B : public A
{
};

The problem is to find the template argument T when a function receives
only a pointer A* (and we know for sure that the A* indeed points to a
B<T>*).

One way is to dynamic_cast to a bunch of know B<T>, but this is kind of
heavy and works only for types that are explicitely taken into account.
Is there a way to retrieve type T for any T, and say print it out?

Thanks

Bolin

re: Finding template argument of child

<gao_bolin@voila.fr> wrote in message
news:1108292120.509189.279300@z14g2000cwz.googlegr oups.com...[color=blue]
> template < typename T >
> class B : public A {};
>
> The problem is to find the template argument T when a function receives
> only a pointer A* (and we know for sure that the A* indeed points to a
> B<T>*).[/color]

In which context do you want to find the T?
If it is just to "say, print", then the easiest way is to define a
non-template intermediate base class which implements the necessary
interface:

#include <iostream>
#include <typeinfo>
#include <string>

struct A
{
virtual ~A() {}
};

struct B_base : A
{
std::string get_T_name() const { return vget_T_name(); }
private:
virtual std::string vget_T_name() const =0;
};

template<typename T>
struct B : B_base
{
private:
std::string vget_T_name() const { return typeid(T).name(); }
};

int main()
{
B<int> b_int;
A& a= b_int;
B_base& b_base= dynamic_cast<b_base&>( a );
std::cout << b_base.get_T_name() << std::endl;
}


Hope it helps,
Ruslan Abdikeev.

re: Finding template argument of child

How about:
class A

{

public:

A(){}

virtual ~A() {}

virtual const type_info & getTypeInfo() const {return typeid(A); }

};

template <class T>

class B : public A

{

public:


virtual const type_info & getTypeInfo() const {return typeid(T); }

};

int main(int argc, char **argv)

{

A anA;

A* pA = new B<int>;

std::cout << anA.getTypeInfo().name() << std::endl;

std::cout << pA->getTypeInfo().name() << std::endl;

return 0;

}

regards,
Aiden

<gao_bolin@voila.fr> wrote in message
news:1108292120.509189.279300@z14g2000cwz.googlegr oups.com...[color=blue]
>I have the following situation:
>
> class A
> {
> public:
> virtual ~A() {}
> };
>
> template < typename T >
> class B : public A
> {
> };
>
> The problem is to find the template argument T when a function receives
> only a pointer A* (and we know for sure that the A* indeed points to a
> B<T>*).
>
> One way is to dynamic_cast to a bunch of know B<T>, but this is kind of
> heavy and works only for types that are explicitely taken into account.
> Is there a way to retrieve type T for any T, and say print it out?
>
> Thanks
>
> Bolin
>[/color]



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