serializable double with precision

[Steph]

When I serialise an object I would like to have a double precision in
the "double" type :

My code:
private double _price = 100;
public double Price
(
get (return;)
set (_price = value;)
}

Serialize :

<price100 </ price>

And i want:

<price100.00 </ price>

How do ?

thanks

[Marc Gravell]

Well, you could perhaps do it manually? I wouldn't do the entire
serialization yourself, but how about:

[XmlIgnore]
public double Price {...}

[XmlElement("Price")]
public string PriceString {
get {return (your expicit Price.ToString() or whatever);}
set {Price = double.Parse(value);}
}

If you do this, you may wish to explicitely use an invariant culture
in the ToString() / Format().

Also - if you are using data-contracts, note that you can happily make
PriceString private; if the intellisense annoys you can can use
[EditorBrowsable({blah}.Never)] to remove it from view.

Marc

[Steph]

Marc Gravell wrote:

Well, you could perhaps do it manually? I wouldn't do the entire
serialization yourself, but how about:

[XmlIgnore]
public double Price {...}

[XmlElement("Price")]
public string PriceString {
get {return (your expicit Price.ToString() or whatever);}
set {Price = double.Parse(value);}
}

If you do this, you may wish to explicitely use an invariant culture
in the ToString() / Format().

Also - if you are using data-contracts, note that you can happily make
PriceString private; if the intellisense annoys you can can use
[EditorBrowsable({blah}.Never)] to remove it from view.

Marc

it's perfect...
i use :
private double _paye = 0;
//[XmlElement(ElementName = "paye")]
[XmlIgnore]
public double Paye
{
get { return _paye; }
set { _paye = value; }
}
[XmlElement("paye")]
public string PayeString
{
get { return Paye.ToString("#0.00"); }
set { double.TryParse(value, out _paye); }
}
and i can continue to use my code ! (public object this[string index])
a minimum code change ! perfect !

great thanks for this tips !