Hi Kevin,
[color=blue]
> In addition...I've tried setting the messagebox to be
> displayed on the Activated event. I've tried using the
> MessageBox owner parameter and passing in the form.[/color]
This is the right direction to pursue. See the code sample below that
extends this idea and should help solving your problem:
protected override void OnActivated(System.EventArgs e)
{
base.OnActivated(e);
if (!_dataPopulated)
{
// THIS IS IMPORTANT!
this.Activate();
// Immediately prevent calling this code for the second time.
// This should be done before any actual work is done. Looks
// strange but works. You might need to re-name the variable to
// make the code more readable.
_dataPopulated = true;
PopulateData();
}
}
--
Dmitriy Lapshin [C# / .NET MVP]
X-Unity Test Studio
http://x-unity.miik.com.ua/teststudio.aspx
Bring the power of unit testing to VS .NET IDE
"Kevin Carter" <anonymous@discussions.microsoft.com> wrote in message
news:0b1e01c39e5e$f3c0a930$a001280a@phx.gbl...[color=blue]
> Hi there...hoping somebody can help me out because I am
> almost ready to pull out my hair.
>
> My problem is as follows:
>
> In a method in my main form (non MDI app), I instantiate
> and .Show another form. As a result of the .Show, the
> form's Load event is called and I have a population
> routine fires off. Normally, all is well and good and the
> new form is active and gets displayed on top of the main
> form.
>
> I need to show a messagebox sometimes while populating the
> new form, and whenever a messagebox is shown, the new form
> always ends up "behind" the old form (but this only
> happens when a messagebox is displayed).
>
> After I .Show the form, I've all of the following tried
> (not all at once):
> newform.BringToFront();
> ...
> newform.Activate();
> ...
> oldform.SendToBack();
> ...
>
> In addition...I've tried setting the messagebox to be
> displayed on the Activated event. I've tried using the
> MessageBox owner parameter and passing in the form.
>
> Does anyone have any ideas? Thanks very much for your
> help.
>
> Kevin
>[/color]
