newby question : function parameter passing

Help. I'm new to php. I wrote a function that did not seem to work so
I checked whether the parameter I was passing to the function was
actually being used. I found that it wasn't. When I run the following
code I get:

Testcheck:

and nothing else. It seems that the variable is not being passed to
the function. Here is the code:

function file_write_position($textcheck) {
print "Testcheck: " . $testcheck . "<br>\n\n";
return;
}

$testcheck="# Test Call Area";
file_write_position($testcheck);

What am I doing wrong??

A

amadain schrieb:The parameter is called $textcheck, but you are using $testcheck inside
the function.

That's funny! Also, you don't need to include the return statement
unless you are returning something.

..oO(amadain)
Set error_reporting to E_ALL in your php.ini.

Micha