A form can have many records. Do you always want to duplicate the *first*
one? Sounds odd.
The Load event is too early to try the paste append.
The Current event is also unusable: As soon as you move to any record, if
the code worked, Access would duplicate it which would load the new record
which would fired the Curent event which would copy it and move to the new
record and so the Current event would fire again and... Fortunately for you,
this doesn't work either.
If there is a valid reason for duplicating the first record in the form as
soon as it opens, I am guessing that you are opening the form with a
WhereCondition so that only the one desired record is loaded. If this is the
case, you could OpenForm, and then trigger the Click event of the button so
the code runs automatically. If the command button is named Command1, you
need to remove the Private keyword from the start of this line:
Private Sub Command1_Click()
You can then execute the code like this:
DoCmd.OpenForm "Form1", WhereCondition:="ID = 99"
Call Form_Form1.Command1_Click
--
Allen Browne - Microsoft MVP. Perth, Western Australia.
Tips for Access users -
http://allenbrowne.com/tips.html
Reply to group, rather than allenbrowne at mvps dot org.
"2D Rick" <rbrowniii@compuserve.com> wrote in message
news:1147798889.621846.40930@j33g2000cwa.googlegro ups.com...[color=blue]
> Access2003 in XP
> If I open a form to a specific record and click on a command button
> with the following code I get a duplcate record:
>
> DoCmd.RunCommand acCmdSelectRecord
> DoCmd.RunCommand acCmdSaveRecord
> DoCmd.RunCommand acCmdCopy
> DoCmd.RunCommand acCmdPasteAppend
> OR
> DoCmd.DoMenuItem acFormBar, acEditMenu, 8, , acMenuVer70
> DoCmd.DoMenuItem acFormBar, acEditMenu, 2, , acMenuVer70
> DoCmd.DoMenuItem acFormBar, acEditMenu, 5, , acMenuVer70 'Paste
> Append
>
> But if I try to run this from and event such as OnLoad, OnCurrent or
> OnTimer I get an error message.
> "The command or action 'Copy' isn't available now."
>
> I know going in that I what a duplicate record so is there a fix for
> this?
>
> Thanks, Rick[/color]
Making a duplicate record 
