 Seeing a function's code in a debugger (dynamic functions)
Is there a way in Firebug to see what code is in a function? All I can
coax out of Firefox is "function()". Same with using Firebug's
console.out.
IE's debugger just tells me it's an Object {...}.
Does anyone know of a way to see the function's code? Getting it into
a string and printing that out would be just dandy.
I'm not looking for a way to see the source (I know how to do that).
I'm changing a function during execution and trying to find a good way
to debug the result. I have my code working now, but it would have
been a lot easier with a way to see what code the function currently
has in it ready to execute.
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