Constant member of a class

#include <iostream>
using namespace std;

class ConstantMember
{
const int m_const;
public:
ConstantMember(int cons = 10):m_const(cons){}
int getConst() const{ return m_const;}
};

int main()
{
ConstantMember X;//(20);
cout << X.getConst();
return 0;
}

the above is a program that was compiled & linked using g++. Is there
any other way to initialise a constant member variable using
constructor while creating objects?

On Fri, 04 Jul 2008 02:08:13 -0700, Anarki wrote:
{There are two points: initialization and constructor body execution, the
reason for const member functions to be initialized in the initializer is
that by the time the constructor body is executed, the initialization is
complete, and for const members, this is not possible because once you
assign the value you can not change it afterwards.

HTH

Of course "const members" not const member functions

On Jul 4, 5:08 am, Anarki <Deepchan...@gmail.comwrote:
well yes, copy ctor which is generated for you in the code above and
should look something like ...

class C
{
const int m;
public:
C(int n = 10) : m(n) { }
C(const C& copy) : m(copy.m) // ... this
{
std::cout << "copy\n";
}
int get() const { return m; }
};

int main()
{
C c;
std::cout << c.get() << std::endl;
C cop(c);
std::cout << cop.get() << std::endl;
}

/*
10
copy
10
*/

#include <iostream>
using namespace std;

class ConstantMember1
{
const int m_const;
public:
ConstantMember1(int cons = 20){m_const = cons;}
int getConst() const{ return m_const;}

};

int main()
{
ConstantMember1 Y;
cout << X.getConst();
return 0;

}


Why doesn't this program compile? What is the difference between the
constructor i gave in first post and this ( ConstantMember() and
ConstantMember1() )

On Jul 14, 3:07*pm, Anarki <Deepchan...@gmail.comwrote:sorry there is a typing mistake in the above code its Y.getConst();
but i have typed X.getConst();

Guys is there way to edit my post where i have made mistakes like the
above?

Anarki wrote:Too many bugs? Your compiler errors should have been clear enough.

The only way to initialise a const member is with an initialiser list.
You used an initialiser list.

--
Ian Collins.

Anarki wrote:No. Cut and paste code you have tried rather than typing it into the
message.

--
Ian Collins.

On Jul 14, 3:16*pm, Ian Collins <ian-n...@hotmail.comwrote:look friend i know the error is due to the constant variable in class.
But why should the compiler raise error? Am looking for more detailed
explanation.i understand i used initialiser list but whats happening inside the
initialiser list? What does the compiler do when it see the
initialiser list. I think u didn't get what i meant. i explain a bit
more what's the difference between a normal constructor and
constructor that uses initialiser list.The answer you gave me was just the technical term/terminology of the
example i posted. But what exactly is happening inside this
initialiser list?? Some one please help......

On Jul 14, 10:07*am, Anarki <Deepchan...@gmail.comwrote:
[snip]Did you read the post by utab that appeared here 10 days ago?
It's still on Google, so you could find it if you looked.
Socks

Anarki wrote:What does you book tell you? This is pretty basic stuff. If you want
to see exactly what your compiler does, look at the generated assembler.

--
Ian Collins.

On Jul 15, 1:08*am, Ian Collins <ian-n...@hotmail.comwrote:Sorry Ian am not a good programmer. I dunno how to get my hands on the
generated assembler and if at all i get my hands on it i dont think i
can understand it. Anyways i am gonna search for the stuff Puppet_sock
said about utab.

Did u mean his post in this thread? if so

Does it really mean that initialization of constant member variable
occurs before the execution of constructor(using initialiser list).

Again, does that mean a member variable of a object get initialized
even before the object is constructed?

Clearing basics of C++ looks real chaos(for me) :)

Anarki wrote:Please don't used txt speak on Usenet.
Yes, members in the initialisation list are initialised before the body
of the constructor is run.
No, the initialisation is one phase of the object's construction.

--
Ian Collins.