Reference are always lvalue?

Hello everyone,


Is the conclusion correct? Both const reference and non-const
reference are lvalue?

I think it is true and I can not find a sample which does not follow
it.


thanks in advance,
George

George2 wrote:If an expression has the type 'reference to T', it's an lvalue. See
[expr]/6. I presume by "const reference" and "non-const reference"
you actually mean "reference to const" and "reference to non-const".

V
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