What happens before main()?

What happens before main()?

Perhaps someone can explain it succintly and perhaps
someone has a link where it is described? crt0.lib or
something like that comes to mind (surely I have the
source code to that given that I have a number of
compilers (some very old) but I'd rather get some
rough idea first of what's happening there). Is it just
setting up an environment in which the C++ library
will work? What happens from the time a program
is started (typing the name on the command line and
pressing enter, for example) until it starts initializing
application program objects and then ending up at main()?

Tony

Tony wrote:It's implementation defined.

Tony wrote:Construction of static objects defined at the namespace
level happens. Everything else is implementation-defined.
Perhaps.
Yes. Probably. In your system, that is.
That's up to the hosting environment and beyond the scope
of this newsgroup.

V
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Noah Roberts wrote:Implementation-specific, but not implementation-defined. The latter is a
technical term in the C++ standard. It requires that the implementation
document its behavior.

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-- Pete
Roundhouse Consulting, Ltd. (www.versatilecoding.com)
Author of "The Standard C++ Library Extensions: a Tutorial and
Reference." (www.petebecker.com/tr1book)

Victor Bazarov wrote:What about static objects at the class level? Is that different?

"Victor Bazarov" <v.Abazarov@comAcast.netwrote in message
news:FIKdncXpibc8EerYnZ2dnUVZ_rWdnZ2d@comcast.com. ..Sounds like something I may be hacking on at some time.
Maybe all that is necessary is the static initialization and
main() is too specialized for a specific paradigm (the UNIX
filter type of program).

Tony

Noah Roberts wrote:The definition of a class's static data member has to appear at
namespace scope so Victor's statement implicitly includes static data
members.

Gavin Deane