combining two vectors

Is there an easy and efficient way to combine two <vector>s, rather
than taking each element from one and adding it to the other?

I haven`t been able to find any guidance on or examples of this
sort of operation.

Thanks, Alan

Alan wrote:vector1.insert( vector1.end(), vector2.begin(), vector2.end() );

--
Ian Collins.

Ian, Thanks! Alan

Ian Collins schrieb:It's easy - yes.
But is it really efficient ?
Isn't it as unefficient as repeatedly calling push_bask() on vector1 ?

/S
--
Stefan Naewe
stefan_DOT_naewe_AT_atlas_DOT_de

Stefan Naewe wrote:No. The iterators that represent the range being copied are random
access iterators, so insert can figure out how many elements will be
added and adjust the size accordingly. Repeatedly calling push_back
could end up reallocating the storage space more than once.

--

-- Pete
Roundhouse Consulting, Ltd. (www.versatilecoding.com)
Author of "The Standard C++ Library Extensions: a Tutorial and
Reference." (www.petebecker.com/tr1book)

Pete Becker schrieb:OK.
But what if I do a vector1.reserve(x) (with a valid x...) before ?
'vector2.end()-vector2.begin()' elements need to be copied after vector1.end(), right?

(Using std::list and std::list::splice() would be more efficient in this case, wouldn't it?)


/S
--
Stefan Naewe
stefan_DOT_naewe_AT_atlas_DOT_de

Stefan Naewe wrote:Why does everyone ask "is this more efficient" in a vacuum?

Have you benchmarked to determine that your vector operations are the
bottleneck? An "efficient" program that doesn't work right is not as
good as an "inefficient" program that does.

Hoare's Law (also attributed to Knuth): "Premature optimization is the
root of all evil".

red floyd wrote:And how is changing from push_back to insert going to make this code not
work right?
Okay, let's all use bubble sort until we can prove that quicksort will
be a better choice.

Sometimes optimization without measurement is perfectly appropriate.
When there's a choice of two ways to do something and one is slower,
choose the other.

for (iter = vector2.begin(); iter != vector2.end(); ++iter)
vector1.push_back(*iter);

versus

vector1.insert(vector1.end(), vector2.begin(), vector2.end());

No contest. Use the latter.

--

-- Pete
Roundhouse Consulting, Ltd. (www.versatilecoding.com)
Author of "The Standard C++ Library Extensions: a Tutorial and
Reference." (www.petebecker.com/tr1book)

Pete Becker wrote:Agreed, maybe the quote should be changed to "Premature
micro-optimisation is the root of all evil" to differentiate between
code tweaks and choice of algorithm.

--
Ian Collins.

* Ian Collins:Isn't that an optimization?

--
A: Because it messes up the order in which people normally read text.
Q: Why is it such a bad thing?
A: Top-posting.
Q: What is the most annoying thing on usenet and in e-mail?

Alf P. Steinbach wrote:More like a design decision.

--
Ian Collins.

* Ian Collins:Well, yes, but isn't that an optimization? <g>

--
A: Because it messes up the order in which people normally read text.
Q: Why is it such a bad thing?
A: Top-posting.
Q: What is the most annoying thing on usenet and in e-mail?