How do I select only the first node from a for-each loop that contains
a the element "photo".

the following xsl finds all "art" elements that have a "photo" element.
The problem is that I only want to output the first found result. The
way I've written the xsl I get a couple "photo" elements.
Here's my xsl:

<xsl:template match="/topixfeed">
<!--some additional stuff happens here that finds the parent of all
"art" elements-->
<xsl:for-each select="art">
<xsl:choose>
<xsl:when test='photo'>
<h3><xsl:number/><xsl:value-of select="title"/></h3>
</xsl:when>
</xsl:choose>
</xsl:for-each>
</div>
</xsl:template>

Thanks for any help...mt

martin.tschofen@gmail.com wrote:[color=blue]
> How do I select only the first node from a for-each loop that contains
> a the element "photo".
>
> the following xsl finds all "art" elements that have a "photo" element.
> The problem is that I only want to output the first found result. The
> way I've written the xsl I get a couple "photo" elements.
> Here's my xsl:
>
> <xsl:template match="/topixfeed">
> <!--some additional stuff happens here that finds the parent of all
> "art" elements-->
> <xsl:for-each select="art">
> <xsl:choose>
> <xsl:when test='photo'>
> <h3><xsl:number/><xsl:value-of select="title"/></h3>
> </xsl:when>
> </xsl:choose>
> </xsl:for-each>
> </div>
> </xsl:template>
>
> Thanks for any help...mt
>[/color]
<http://zvon.org/xxl/XPathTutorial/Output/example4.html#b9b1c33c23>

So you might try

<xsl:template match="/topixfeed/art/photo[1]">
<h3><xsl:number/><xsl:value-of select="title"/></h3>
</xsl:template>
<xsl:template match="/topixfeed/art/photo">
<!--Your action for all the others but the first onee -->
</xsl:template>

HTH
--
Volkm@r

<martin.tschofen@gmail.com> wrote in message
news:1116387456.198555.8000@g49g2000cwa.googlegrou ps.com...[color=blue]
> How do I select only the first node from a for-each loop that contains
> a the element "photo".
>
> the following xsl finds all "art" elements that have a "photo" element.
> The problem is that I only want to output the first found result. The[/color]

This is an artificially created problem. If only the first element in the
node-set must be processed, then instead of:

<xsl:for-each select="$someNode-set">
<!-- Whatever processing is necessary here -->
</xsl:for-each>

Use:
<xsl:for-each select="($someNode-set")[1]>
<!-- Whatever processing is necessary here -->
</xsl:for-each>


Cheers,
Dimitre Novatchev
[color=blue]
> way I've written the xsl I get a couple "photo" elements.
> Here's my xsl:
>
> <xsl:template match="/topixfeed">
> <!--some additional stuff happens here that finds the parent of all
> "art" elements-->
> <xsl:for-each select="art">
> <xsl:choose>
> <xsl:when test='photo'>
> <h3><xsl:number/><xsl:value-of select="title"/></h3>
> </xsl:when>
> </xsl:choose>
> </xsl:for-each>
> </div>
> </xsl:template>
>
> Thanks for any help...mt
>[/color]