public void DoSomething<T>(object value)
{
<code omitted>
}

public void DoSomething<T>()
{
How do I now call this.DoSomething<T>(null);
}



Thanks


Pete

Pete,

You will have to cast the null, like so:

this.DoSomething<T>((object) null);


--
- Nicholas Paldino [.NET/C# MVP]
- mvp@spam.guard.caspershouse.com

"Peter Morris" <mrpmorrisNO@SPAMgmail.comwrote in message
news:eLZx5yRCJHA.4884@TK2MSFTNGP02.phx.gbl...

public void DoSomething<T>(object value)
{
<code omitted>
}
>
public void DoSomething<T>()
{
How do I now call this.DoSomething<T>(null);
}
>
>
>
Thanks
>
>
Pete

Ahh. I thought it *should* work. Thanks!


Pete

On Aug 28, 6:45*pm, "Peter Morris" <mrpmorri...@SPAMgmail.comwrote:

public void DoSomething<T>(object value)
{
* * <code omitted>
>
}
>
public void DoSomething<T>()
{
* * How do I now call this.DoSomething<T>(null);
>
}

With the code as written, it should be just "DoSomething<T>(null)" -
there are no ambiguities here. Perhaps you've meant the first
signature to be "DoSomething<T>(T)"? Then you could either use the
cast as suggested, or explicitly specify T on call:
"DoSomething<object>(null)".

On Aug 28, 6:45*pm, "Peter Morris" <mrpmorri...@SPAMgmail.comwrote:

public void DoSomething<T>(object value)
{
* * <code omitted>
>
}
>
public void DoSomething<T>()
{
* * How do I now call this.DoSomething<T>(null);
>
}

With the code as written, it should be just "DoSomething<T>(null)" -
there are no ambiguities here. Perhaps you've meant the first
signature to be "DoSomething<T>(T)"? Then you could either use the
cast as suggested, or explicitly specify T on call:
"DoSomething<object>(null)".