How to check if an object has defined setter?
Question posted by: Piotr K
(Guest)
on
August 27th, 2008 08:45 PM
Hi!
Ok, so I have small problem and can't find solution to it.. Is there
any way to check if an object has defined setter? In other words - if
it's value can be changed?
Small example:
var el = document.getElementById('element');
el.style = "smth";
Browser will throw exception, I can use try..catch but is there way to
just write a function like hasSetter() ?
Thanks fo help!
3
Answers Posted
Piotr K wrote:
Quote:
Originally Posted by
Hi!
>
Ok, so I have small problem and can't find solution to it.. Is there
any way to check if an object has defined setter? In other words - if
it's value can be changed?
>
Small example:
>
var el = document.getElementById('element');
>
el.style = "smth";
>
Browser will throw exception, I can use try..catch but is there way to
just write a function like hasSetter() ?
>
To look up a setter in environments that support that:
if("__lookupSetter__" in el.style
&& el.style.__lookupSetter__("color")) {
}
But that would not tell you if the value can be changed, or what
acceptable values are. You'd just have to know it. For example, given el
is an HTMLElement:-
el.style.color = null;
Would be a mistake.
If there were edge cases that couldn't be eliminated, you could use
try/catch. But that would add clutter and slow the program down.
Garrett
Piotr K wrote:
Quote:
Originally Posted by
Ok, so I have small problem and can't find solution to it.. Is there
any way to check if an object has defined setter? In other words - if
it's value can be changed?
No, but you can test whether the value changed after you tried.
Quote:
Originally Posted by
Small example:
>
var el = document.getElementById('element');
>
el.style = "smth";
>
Browser will throw exception,
BAD. The `style' property of element objects is implemented as a reference
to an object, and its interface specifies it as being read-only.
Quote:
Originally Posted by
I can use try..catch but is there way to just write a function like
hasSetter() ?
No. Adhering to standards stands the best chance of not throwing an
exception here.
<http://www.w3.org/TR/DOM-Level-2-Style/css.html#CSS-ElementCSSInlineStyle>
PointedEars
--
Prototype.js was written by people who don't know javascript for people
who don't know javascript. People who don't know javascript are not
the best source of advice on designing systems that use javascript.
-- Richard Cornford, cljs, <f806at$ail$1$8300dec7@news.demon.co.uk>
On Aug 27, 10:50 pm, Thomas 'PointedEars' Lahn <PointedE...@web.de>
wrote:
Quote:
Originally Posted by
Piotr K wrote:
Quote:
Originally Posted by
Ok, so I have small problem and can't find solution to it.. Is there
any way to check if an object has defined setter? In other words - if
it's value can be changed?
>
No, but you can test whether the value changed after you tried.
>
Quote:
Originally Posted by
Small example:
>
Quote:
Originally Posted by
var el = document.getElementById('element');
>
Quote:
Originally Posted by
el.style = "smth";
>
Quote:
Originally Posted by
Browser will throw exception,
>
BAD. The `style' property of element objects is implemented as a reference
to an object, and its interface specifies it as being read-only.
>
Quote:
Originally Posted by
I can use try..catch but is there way to just write a function like
hasSetter() ?
>
No. Adhering to standards stands the best chance of not throwing an
exception here.
>
<http://www.w3.org/TR/DOM-Level-2-Style/css.html#CSS-ElementCSSInlineS...>
>
PointedEars
--
Prototype.js was written by people who don't know javascript for people
who don't know javascript. People who don't know javascript are not
the best source of advice on designing systems that use javascript.
-- Richard Cornford, cljs, <f806at$ail$1$8300d...@news.demon.co.uk>
Do what ever you need to try and do in a try and catch statement ...
e.g
var worked = false;
try
{
var el = document.getElementById('element');
el.style = "smth";
worked=true;
}catch(e)
{
//in here you can alert(e.message); or set an internal error message
}
if(worked==true)
{
//worked
}else{
//didnt work
}
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