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  #1  
Old July 20th, 2008, 04:25 PM
Kless
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Posts: n/a
Default Passing keywords

I've a constructor with several values that must be used by any
functions:

---------------
class foo:

def __init__(self, foo1, foo2, foon):

self.__check(foo1=foo1, foo2=foo2, foon=foon)
self.__check2(foo1=foo1, foo2=foo2, foon=foon)

def __check(self, foo1, foo2, foon):
...

def __check2(self, foo1, foo2, foon):
...
---------------

How simplify all that?

I could use the next but I don't think...

---------------
def __check(self, **keywords):
---------------
  #2  
Old July 20th, 2008, 04:55 PM
Fredrik Lundh
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Posts: n/a
Default Re: Passing keywords

Kless wrote:
Quote:
I could use the next but I don't think...
>
---------------
def __check(self, **keywords):
---------------
don't think what?

if you keep using the same variables in all submethods you call from a
method inside the class, why not make them attributes?

otherwise, using the **-form when *calling* the methods might work. you
can use the **-form in the functions to ignore arguments that you're not
interested in.

self.__check(**kwargs)
self.__check2(**kwargs)

def __check(self, foo1, foo2, **extra):
# use foo1 and foo2 here; ignore the rest

etc.

</F>

 

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