Launching a process (exe) using the same process id as the launcher

Question posted by: franckspike (Guest) on July 3rd, 2008 10:05 PM

Launching a process (exe) using the same process id as the launcher,
how is it possible ?

I want my VCStudio to launch my executable (which is not in
developpement) and this exe will launch the exe module I am currently
developping with the correct arguments, I want to debug it not the
wrapper that launched it

VCStudio starts as debug --A which starts --B which loads -->
C.dll which I want to debug

How can B have the same process id as A ??
or
How can I make VCStudio attach to B without doing it manualy ?

thanx

Boris

Guest

n/a Posts

July 3rd, 2008
10:35 PM
#2

Re: Launching a process (exe) using the same process id as the launcher

On Fri, 04 Jul 2008 00:02:51 +0200, franckspike <franckspike@gmail.com>
wrote:

Quote:

Launching a process (exe) using the same process id as the launcher,
how is it possible ?
>
I want my VCStudio to launch my executable (which is not in
developpement) and this exe will launch the exe module I am currently
developping with the correct arguments, I want to debug it not the
wrapper that launched it
>
VCStudio starts as debug --A which starts --B which loads -->
C.dll which I want to debug
>
How can B have the same process id as A ??
or
How can I make VCStudio attach to B without doing it manualy ?

If you put __debugbreak() into the module which you want to debug you can
attach VC++ to the newly started process rather easily (see
http://msdn.microsoft.com/en-us/library/f408b4et.aspx). And please ask in
a VC++ newsgroup next time if you have a VC++-related question.

Boris

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