for loop question

Question posted by: boomba (Newbie) on May 15th, 2008 12:40 PM

im trying to modify this code using a "for" loop to create 'numPlayers' players. That is, if the user types in 3 for 'numPlayers', then it should loop 3 times and create 3 players.

private void readPlayers()
{

int numPlayers = askForInt("How many players will play?");
String name = askForString("What is player 1's name?");
Player player = new Player(name);
player.enterWorld(world);
}
any suggestions ??? thankyou

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JosAH

Chief Editor

6,993 Posts

May 15th, 2008
12:46 PM
#2

Re: for loop question

If I add a new second line like this:

Code: ( text )

for (int i= 0; i < numPlayers; i++) {
...
}

... you only have to fill in the blanks and probably create a Player array before
the loop starts.

kind regards,

Jos

boomba

Newbie

5 Posts

May 15th, 2008
12:51 PM
#3

Re: for loop question

would i just fill out what i had before in the blanks

boomba

Newbie

5 Posts

May 15th, 2008
01:08 PM
#4

Re: for loop question

Quote:

Originally Posted by JosAH

If I add a new second line like this:

Code: ( text )

for (int i= 0; i < numPlayers; i++) {
...
}

... you only have to fill in the blanks and probably create a Player array before
the loop starts.

kind regards,

Jos

i get a .class error saying .class expected

JosAH

Chief Editor

6,993 Posts

May 15th, 2008
01:17 PM
#5

Re: for loop question

Quote:

Originally Posted by boomba

i get a .class error saying .class expected

If you get a compilation error or a runtime error you can't figure out yourself post
the complete error message and the relevant code that caused the error. You
can't expect from us to be psychic or own chrystal balls. btw, when you submit
code look at the little legenda to the right of the edit window. Enclose your code
in those code tags for readability reasons.

If you want 'n' players you can define an array with 'n' elements:

Code: ( text )

Player[] player= new Player[n];

next you have to create each of those n players just as you created that single
player. Obviously you can and have to do that in a simple loop; each pass through
that loop creates another Player.

kind regards,

Jos

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