Dynamically change an image based on document.URL - Javascript / DHTML / Ajax Forum

Hello,

The objective of this script is to show visitors who found my site by clicking on one of our Google Adwords a specific telephone number (in graphic form) for the sake of tracking.

Here is the code I have been working on. My issue lies within the document.URL area of the script. I tried this code without declaring the source variable, but the script would redirect me to the document.URL declaration.

After running this code on a test page, it now displays the first image in the series, but should be showing the second image as the page I am viewing it on does not have the URL tied to it.

<script language = “javascript” type=”text/javascript”>

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function adWords()
 
{
 
source=document.URL     <!-- If I eliminate this declaration and just use document.URL in the IF statement, the page gets redirected to that URL
 
if(source="http://www.appletreeanswers.com/index.html") { 
 
document.write("<IMG SRC='/normalimage.jpg'>")
 
}else{
 
document.write("<IMG SRC='/adwordimage.jpg'>")
 
 }
 
}

-->

</script>

<script language="javascript" type="text/javascript">

adWords();

</script>

Thanks!

poe

Newbie

31 Posts

March 29th, 2008
01:57 AM
#2

Re: Dynamically change an image based on document.URL

The reason the page gets redirected is because your if statement is making an assignment instead of a comparison.

What you have: blah = blah2

What you need: blah == blah2

With what you have, as soon as you assign document.URL to something, the page location changes.

ccountey

Newbie

8 Posts

March 30th, 2008
01:28 AM
#3

Re: Dynamically change an image based on document.URL

Quote:

Thanks, I am very new at JS, so I appreciate you taking the time to answer a simple question.

Chris

acoder

Site Moderator

11,501 Posts

April 1st, 2008
11:47 AM
#4

Re: Dynamically change an image based on document.URL

Just a note: document.URL is read-only or, at least, should be. IE lets you set it.

For cross-browser functionality, if you ever need to change the URL, use location.href.