Python beginner here.

For a string 'ABBBCC', I want to produce a list ['A', 'BBB', 'CC'].
That is, break the string into pieces based on change of character.
What's the best way to do this in Python?

Using Python 2.5.1, I tried:

import re
s = re.split(r'(?<=(.))(?!\1)', 'ABBBCC')
for e in s: print e

but was surprised when it printed:

ABBBCC

I expected something like:

A
A
BBB
B
CC
C

(the extra fields because of the capturing parens).

Thanks,
/-\



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On Jul 28, 9:46 pm, Andrew Savige <ajsav...@yahoo.com.auwrote:

Python beginner here.
>
For a string 'ABBBCC', I want to produce a list ['A', 'BBB', 'CC'].
That is, break the string into pieces based on change of character.
What's the best way to do this in Python?
>
Using Python 2.5.1, I tried:
>
import re
s = re.split(r'(?<=(.))(?!\1)', 'ABBBCC')
for e in s: print e
>
but was surprised when it printed:
>
ABBBCC
>
I expected something like:
>
A
A
BBB
B
CC
C
>
(the extra fields because of the capturing parens).

Using itertools:

import itertools

s = 'ABBBCC'
print [''.join(grp) for key, grp in itertools.groupby(s)]


Using re:

import re

pat = re.compile(r'((\w)\2*)')
print [t[0] for t in re.findall(pat, s)]


By the way, your pattern seems to work in perl:

$ perl -le '$, = " "; print split(/(?<=(.))(?!\1)/, "ABBBCC");'
A A BBB B CC C

Was that the type of regular expressions you were expecting?

--
Hope this helps,
Steven