Hi, this is a oversimplification of my problem:

I have two functions:

double foo(int param);
int foo(int param);

I want 'double function' to be called if param=1
and 'int function' if param=2

foo(1) => double foo(1)
foo(2)=> int foo(2)

Is this possible?

Thanks

dropy wrote:[color=blue]
> Hi, this is a oversimplification of my problem:
>
> I have two functions:
>
> double foo(int param);
> int foo(int param);
>
> I want 'double function' to be called if param=1
> and 'int function' if param=2
>
> foo(1) => double foo(1)
> foo(2)=> int foo(2)
>
> Is this possible?[/color]

Nope. You can neither overload by argument _value_ nor by return value.

HTH,
--ag



--
Artie Gold -- Austin, Texas

On Mon, 28 Jul 2003 22:13:56 +0200, "dropy" <dropy@dododo.com> wrote:
[color=blue]
>Hi, this is a oversimplification of my problem:
>
>I have two functions:
>
> double foo(int param);
> int foo(int param);
>
>I want 'double function' to be called if param=1
>and 'int function' if param=2
>
>foo(1) => double foo(1)
>foo(2)=> int foo(2)
>
>Is this possible?[/color]

A simple way would be

double d_foo();
int i_foo();

int foo(int param)
{
if (param == 1)
d_foo();
else if (param == 2)
i_foo();
}

Another way would be

template <int param> class foo;

template <>
class foo<1>
{
public:
double operator()( /* something */ )
{
// do something
}
};

template <>
class foo<2>
{
public:
int operator()( /* seomthing */ )
{
// do something
}
};

int main()
{
foo<1> f;
f(); // calls double operator()

foo<2> g;
g(); // calls int operator()
}

Jonathan