Hello Friends
How are you?
I came with a problem near you.
I want to upload a image to my ftp, iam getting this below error. i have a
code which is working in my local system, i have an idea that we need to
provide permissions to upload(like username password) but where we have to
provide those details can you please tell me.
Microsoft VBScript runtime error '800a0046'
Permission denied
/asp/gg/upload/Upload.asp, line 109
can you please help me out of this, Thanks a lot.
my code : the below code is working in local system
<%Response.Buffer = true
Function BuildUpload(RequestBin)
'Get the boundary
PosBeg = 1
PosEnd = InstrB(PosBeg,RequestBin,getByteString(chr(13)))
boundary = MidB(RequestBin,PosBeg,PosEnd-PosBeg)
boundaryPos = InstrB(1,RequestBin,boundary)
'Get all data inside the boundaries
Do until (boundaryPos=InstrB(RequestBin,boundary &
getByteString("--")))
'Members variable of objects are put in a dictionary object
Dim UploadControl
Set UploadControl = CreateObject("Scripting.Dictionary")
'Get an object name
Pos =
InstrB(BoundaryPos,RequestBin,getByteString("Conte nt-Disposition"))
Pos = InstrB(Pos,RequestBin,getByteString("name="))
PosBeg = Pos+6
PosEnd = InstrB(PosBeg,RequestBin,getByteString(chr(34)))
Name = getString(MidB(RequestBin,PosBeg,PosEnd-PosBeg))
PosFile =
InstrB(BoundaryPos,RequestBin,getByteString("filen ame="))
PosBound = InstrB(PosEnd,RequestBin,boundary)
'Test if object is of file type
If PosFile<>0 AND (PosFile<PosBound) Then
'Get Filename, content-type and content of file
PosBeg = PosFile + 10
PosEnd = InstrB(PosBeg,RequestBin,getByteString(chr(34)))
FileName = getString(MidB(RequestBin,PosBeg,PosEnd-PosBeg))
'Add filename to dictionary object
UploadControl.Add "FileName", FileName
Pos =
InstrB(PosEnd,RequestBin,getByteString("Content-Type:"))
PosBeg = Pos+14
PosEnd = InstrB(PosBeg,RequestBin,getByteString(chr(13)))
'Add content-type to dictionary object
ContentType =
getString(MidB(RequestBin,PosBeg,PosEnd-PosBeg))
UploadControl.Add "ContentType",ContentType
'Get content of object
PosBeg = PosEnd+4
PosEnd = InstrB(PosBeg,RequestBin,boundary)-2
Value = MidB(RequestBin,PosBeg,PosEnd-PosBeg)
Else
'Get content of object
Pos = InstrB(Pos,RequestBin,getByteString(chr(13)))
PosBeg = Pos+4
PosEnd = InstrB(PosBeg,RequestBin,boundary)-2
Value = getString(MidB(RequestBin,PosBeg,PosEnd-PosBeg))
End If
UploadControl.Add "Value" , Value
UploadRequest.Add name, UploadControl
BoundaryPos=InstrB(BoundaryPos+LenB(boundary),Requ estBin,boundary)
Loop
End Function
Function getByteString(StringStr)
For i = 1 to Len(StringStr)
char = Mid(StringStr,i,1)
getByteString = getByteString & chrB(AscB(char))
Next
End Function
Function getString(StringBin)
getString =""
For intCount = 1 to LenB(StringBin)
getString = getString & chr(AscB(MidB(StringBin,intCount,1)))
Next
End Function
If request("Action")="1" then
Response.Clear
byteCount = Request.TotalBytes
RequestBin = Request.BinaryRead(byteCount)
Set UploadRequest = CreateObject("Scripting.Dictionary")
BuildUpload(RequestBin)
If UploadRequest.Item("blob").Item("Value") <"" Then
contentType = UploadRequest.Item("blob").Item("ContentType")
filepathname = UploadRequest.Item("blob").Item("FileName")
filename =
Right(filepathname,Len(filepathname)-InstrRev(filepathname,"\"))
FolderName = UploadRequest.Item("where").Item("Value")
Path = Mid(Request.ServerVariables("PATH_TRANSLATED"), 1,
Len(Request.ServerVariables("PATH_TRANSLATED")) -
Len(Request.ServerVariables("PATH_INFO"))) & "\"
ToFolder = Path & FolderName
value = UploadRequest.Item("blob").Item("Value")
filename = ToFolder & "\" & filename
Set MyFileObject =
Server.CreateObject("Scripting.FileSystemObject")
Set objFile = MyFileObject.CreateTextFile(filename)
For i = 1 to LenB(value)
objFile.Write chr(AscB(MidB(value,i,1)))
Next
objFile.Close
Set objFile = Nothing
Set MyFileObject = Nothing
End If
Set UploadRequest = Nothing
End If%>
<form METHOD="POST" ENCTYPE="multipart/form-data"
action="Upload.asp?Action=1" name="form1" id="form1">
<table cellspacing="0" cellpadding="3" width="100%" border="0">
<tr>
<td>
<b>Select a file to upload: </b>
</td>
<td>
<input TYPE="file" NAME="blob" value>
<input TYPE="HIDDEN" NAME="where" value="Images">
</td>
<tr>
<tr>
<td colspan="2" align="center">
<input TYPE="submit" NAME="Upload" Value="Click to Upload">
</td>
</tr>
</table>
</form>
upload image to FTP 
