Help | Site Map
Connecting Tech Pros Worldwide
 
 
LinkBack Thread Tools
  #1  
Old December 7th, 2006, 02:35 AM
heng
Guest
 
Posts: n/a
Default which constructor is used in the direct-initialization?

class A
{
public:
int x;
A(int x_=0):x(x_){}
};

int main()
{
A obj1(99); //user-defined constructor is used
A obj2=obj1; //compiler-defined copy constructor is used
A obj3(obj1); //which constructor is used ? I am surprised that
this kind of direct-initialization
//works

Thanks for your kind help !

  #2  
Old December 7th, 2006, 02:55 AM
Salt_Peter
Guest
 
Posts: n/a
Default Re: which constructor is used in the direct-initialization?


heng wrote:
Quote:
class A
{
public:
int x;
A(int x_=0):x(x_){}
};
Why not test it?

#include <iostream>

class A {
int x;
public:
A( int n = 0 ) : x(n) { std::cout << "A(int)\n"; }
A( const A& copy )
{
std::cout << "A copy\n";
x = copy.x;
}
};
Quote:
>
int main()
{
A obj1(99); //user-defined constructor is used
A obj2=obj1; //compiler-defined copy constructor is used
A obj3(obj1); //which constructor is used ? I am surprised that
this kind of direct-initialization
//works
>
Thanks for your kind help !
There is absolutely no difference between the following 2 statements:

A obj2 = obj1;
A obj2( obj1 );

  #3  
Old December 7th, 2006, 03:05 AM
heng
Guest
 
Posts: n/a
Default Re: which constructor is used in the direct-initialization?

Salt_Peter wrote:


Thanks. But you explicitly define the copy constructor in your example,
I mean, without the explicit copy constructor, which constructor is
used in the expression like

A obj2(obj1);

is it still the copy constructor?

  #4  
Old December 7th, 2006, 03:15 AM
Victor Bazarov
Guest
 
Posts: n/a
Default Re: which constructor is used in the direct-initialization?

heng wrote:
Quote:
Salt_Peter wrote:
>
>
Thanks. But you explicitly define the copy constructor in your
example, I mean, without the explicit copy constructor, which
constructor is used in the expression like
>
A obj2(obj1);
>
is it still the copy constructor?
Probably. If you don't declare one, it will be declared for you,
and defined (if possible).

V
--
Please remove capital 'A's when replying by e-mail
I do not respond to top-posted replies, please don't ask


  #5  
Old December 7th, 2006, 03:55 AM
Salt_Peter
Guest
 
Posts: n/a
Default Re: which constructor is used in the direct-initialization?


heng wrote:
Quote:
Salt_Peter wrote:
>
>
Thanks. But you explicitly define the copy constructor in your example,
I mean, without the explicit copy constructor, which constructor is
used in the expression like
>
A obj2(obj1);
>
is it still the copy constructor?
Yes, the compiler must provide a copy ctor unless you explicitly
prevent it.
Otherwise, the above would generate an error.
So why not implement the copy to match your needs?

To push the logic a little further, how come the following works?

class A {
};

int main()
{
A a; // def ctor
A b(a); // copy ctor
a = b; // assignment - not a copy!!!
}

  #6  
Old December 7th, 2006, 04:25 AM
Ivan Novick
Guest
 
Posts: n/a
Default Re: which constructor is used in the direct-initialization?

heng wrote:
Quote:
class A
{
public:
int x;
A(int x_=0):x(x_){}
};
>
int main()
{
A obj1(99); //user-defined constructor is used
A obj2=obj1; //compiler-defined copy constructor is used
A obj3(obj1); //which constructor is used ? I am surprised that
this kind of direct-initialization
//works
>
Thanks for your kind help !
That is part of the definition of the language. If you do not define
your own copy constructor the compiler will create an implicit one for
you. The compiler created copy constructor performs a memberwise copy
of its subobjects.
-
Ivan
http://www.0x4849.net

 

Bookmarks

Thread Tools

Posting Rules
You may not post new threads
You may not post replies
You may not post attachments
You may not edit your posts

BB code is On
Smilies are Off
[IMG] code is Off
HTML code is Off
Trackbacks are On
Pingbacks are On
Refbacks are On

What is Bytes?

We are a network of experts and professionals in IT and software development that help one another with answers to tough questions and share insights. Get the best answers to your questions from over network members.
Post your question now . . .
It's fast and it's free

Popular Articles