August 2nd, 2006, 12:45 PM
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Datetime objects
How can I find days and minutes difference between two datetime
objects?
For example If I have
b=datetime.datetime(2006, 8, 2, 8, 57, 28, 687000)
a=datetime.datetime(2006, 8, 1, 18, 19, 45, 765000)
Thank you for help
L.
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August 2nd, 2006, 12:45 PM
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Re: Datetime objects
Lad wrote:
Quote:
How can I find days and minutes difference between two datetime
objects?
For example If I have
b=datetime.datetime(2006, 8, 2, 8, 57, 28, 687000)
a=datetime.datetime(2006, 8, 1, 18, 19, 45, 765000)
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a - b
Lookup datetime.timedelta - all of this is neatly documented.
Diez
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August 2nd, 2006, 01:15 PM
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Re: Datetime objects
Sybren Stuvel wrote:
Quote:
Lad enlightened us with:
Quote:
How can I find days and minutes difference between two datetime
objects?
For example If I have
b=datetime.datetime(2006, 8, 2, 8, 57, 28, 687000)
a=datetime.datetime(2006, 8, 1, 18, 19, 45, 765000)
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>
diff = b - a
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Ok, I tried
datetime.timedelta(0, 52662, 922000) datetime.timedelta(-999999999)
which is not good for me.
So I tried to use toordinal like this
diff=b.toordinal()-a.toordinal()
but I get
diff=1
Why?
where do I make a mistake?
Thank you for help
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August 2nd, 2006, 01:55 PM
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Re: Datetime objects
Lad wrote:
Quote:
Sybren Stuvel wrote:
Quote:
Lad enlightened us with:
Quote:
How can I find days and minutes difference between two datetime
objects?
For example If I have
b=datetime.datetime(2006, 8, 2, 8, 57, 28, 687000)
a=datetime.datetime(2006, 8, 1, 18, 19, 45, 765000)
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diff = b - a
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>
Ok, I tried
>datetime.timedelta(0, 52662, 922000)datetime.timedelta(-999999999)
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Reread the manual:
1. "min" is minIMUM, not minUTES
2. You need: 0 52662 922000
Quote:
Quote:
Quote:
>>minutes = (diff.seconds + diff.microseconds / 1000000.0) / 60.0
>>minutes
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877.71536666666668
Quote:
>
>
which is not good for me.
>
So I tried to use toordinal like this
diff=b.toordinal()-a.toordinal()
>
but I get
diff=1
>
Why?
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because toordinal() works only on the date part, ignoring the time
part.
HTH,
John
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August 2nd, 2006, 04:45 PM
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Re: Datetime objects
John Machin wrote:
Quote:
Lad wrote:
Quote:
Sybren Stuvel wrote:
Quote:
Lad enlightened us with:
How can I find days and minutes difference between two datetime
objects?
For example If I have
b=datetime.datetime(2006, 8, 2, 8, 57, 28, 687000)
a=datetime.datetime(2006, 8, 1, 18, 19, 45, 765000)
>
diff = b - a
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Ok, I tried
datetime.timedelta(0, 52662, 922000) datetime.timedelta(-999999999)
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>
Reread the manual:
>
1. "min" is minIMUM, not minUTES
>
2. You need:052662922000
Quote:
Quote:
>minutes = (diff.seconds + diff.microseconds / 1000000.0) / 60.0
>minutes
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877.71536666666668
Quote:
which is not good for me.
So I tried to use toordinal like this
diff=b.toordinal()-a.toordinal()
but I get
diff=1
Why?
|
>
because toordinal() works only on the date part, ignoring the time
part.
>
HTH,
John
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Thank you for the explanation
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