Copying xml declaration with XSLT

* Dennis Benzinger wrote in comp.text.xml:

That's not possible without using processor-specific extensions; in the
XPath data model, which XSLT operates on, this information is lost and
re-created based on among other things the xsl:output settings (e.g.,
you can "change" the character encoding which would require to change
the encoding specified by the xsl:output element).
--
Björn Höhrmann · mailto:bjoern@hoehrmann.de · http://bjoern.hoehrmann.de
Weinh. Str. 22 · Telefon: +49(0)621/4309674 · http://www.bjoernsworld.de
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(Use case: I have a xml document where I just want to add a processing

The xml declaration is not a processing instruction. A processing
instruction is represented in the XML Infoset and can easily be copied from
one document to another.

Cheers,
Dimitre Novatchev


"Dennis Benzinger" <Dennis.Benzinger@gmx.netwrote in message
news:44b627ed$1@news.uni-ulm.de...

Dimitre Novatchev wrote:

Yes, I know that. But I don't want to copy the xml declaration, I want
to add a processing instruction.


So please show me how.

Dennis

>A processing instruction is represented in the XML Infoset and can easily

Use the <xsl:copy-ofinstruction.

Here's a simple example:

This transformation:

<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:output omit-xml-declaration="yes"/>

<xsl:template match="node()|@*">
<xsl:copy>
<xsl:apply-templates select="node()|@*"/>
</xsl:copy>
</xsl:template>

<xsl:template match="processing-instruction()">
<xsl:copy-of select="."/>
</xsl:template>
</xsl:stylesheet>

when applied on this source xml document:

<t>
<?PI xxx="yyy" ?>
</t>

produces this result:

<t>
<?PI xxx="yyy" ?>
</t>

The processing instruction matched by the 2nd (last template) and this
template is selected for processing it. The action is simply to copy the
current node (the processing instruction) to the output.


Hope this helps.

Cheers,
Dimitre Novatchev


"Dennis Benzinger" <Dennis.Benzinger@gmx.netwrote in message
news:44ba96d9$1@news.uni-ulm.de...

Dennis Benzinger wrote:

Must have been quite confused when I wrote this. Of course I want to
copy a xml declaration like I wrote in my first post. After all I want
to add a processing instruction to a xml document without modifing the
rest of the document. But as Bjoern Hoermann wrote that's not possible
with XSLT. Maybe XSLT 2.0 helps?


Thanks to Dimitre Novatchev for anwsering my useless question.


Dennis