Thanks for your reply John,
As for how to programmatically interact with the upload page in client .net
application, have you had a chance to see the code in the article I
provided or my attached demo? I'm sorry for my carelessness since I
assumed that you'll have a look at those article or my demo. Anyway, here
are some code snippet on using webclient or httpwebrequest to post file
stream:
#using WebClient
string url = "http://myserver/myapp/upload.aspx";
string file = "c:\\files\\test.jpg";
WebClient wc = new WebClient();
wc.UploadFile(url,"post",file);
#using httpWebrequest:
private void UploadFilesToRemoteUrl(string url, string[] files, string
logpath)
{
long length = 0;
string boundary = "----------------------------" +
DateTime.Now.Ticks.ToString("x");
HttpWebRequest httpWebRequest2 = (HttpWebRequest)WebRequest.Create(url);
httpWebRequest2.ContentType = "multipart/form-data; boundary=" + boundary;
httpWebRequest2.Method = "POST";
httpWebRequest2.KeepAlive = true;
httpWebRequest2.Credentials =
System.Net.CredentialCache.DefaultCredentials;
Stream memStream = new System.IO.MemoryStream();
byte[] boundarybytes = System.Text.Encoding.ASCII.GetBytes("\r\n--" +
boundary + "\r\n");
memStream.Write(boundarybytes,0,boundarybytes.Leng th);
length += boundarybytes.Length;
string headerTemplate = "Content-Disposition: form-data; name=\"{0}\";
filename=\"{1}\"\r\n Content-Type: application/octet-stream\r\n\r\n";
for(int i=0;i<files.Length;i++)
{
string header = string.Format(headerTemplate,"file"+i,files[i]);
byte[] headerbytes = System.Text.Encoding.UTF8.GetBytes(header);
memStream.Write(headerbytes,0,headerbytes.Length);
length += headerbytes.Length;
FileStream fileStream = new FileStream(files[i], FileMode.Open,
FileAccess.Read);
byte[] buffer = new byte[1024];
int bytesRead = 0;
while ( (bytesRead = fileStream.Read(buffer, 0, buffer.Length)) != 0 )
{
memStream.Write(buffer, 0, bytesRead);
length += bytesRead;
}
memStream.Write(boundarybytes,0,boundarybytes.Leng th);
length += boundarybytes.Length;
fileStream.Close();
}
httpWebRequest2.ContentLength = memStream.Length;
Stream requestStream = httpWebRequest2.GetRequestStream();
memStream.Position = 0;
byte[] tempBuffer = new byte[memStream.Length];
memStream.Read(tempBuffer,0,tempBuffer.Length);
memStream.Close();
requestStream.Write(tempBuffer,0,tempBuffer.Length );
requestStream.Close();
WebResponse webResponse2 = httpWebRequest2.GetResponse();
Stream stream2 = webResponse2.GetResponseStream();
StreamReader reader2 = new StreamReader(stream2);
MessageBox.Show(reader2.ReadToEnd());
webResponse2.Close();
httpWebRequest2 = null;
webResponse2 = null;
}
As we can see, weclient has encapsulated the underlying details of using
httpwebrequest to post data and the code will be very simple. However,
using httpwebrequest directly will give us more control over the posted
data stream as my above function inject multi file stream into the single
HttP request message.
Hope helps.
Steven Cheng
Microsoft Online Support
Get Secure!
www.microsoft.com/security
(This posting is provided "AS IS", with no warranties, and confers no
rights.)
